A) \[{{\,}^{61}}Co\]
B) \[{{\,}^{60}}Ni\]
C) \[{{\,}^{59}}Ni\]
D) \[{{\,}^{60}}Cu\]
Correct Answer: B
Solution :
Key Idea: (i) The sum of atomic masses of reactants = the sum of atomic masses of products (ii) The sum of atomic number of reactant = the sum of atomic number of products (iii) \[\beta -\]particles is electron and loss of \[\beta -\]particle results in increases in atomic number by 1 and atomic mass remains same \[_{27}^{60}Co\xrightarrow{{}}\underset{\beta \,particle}{\mathop{_{28}^{60}Ni{{+}^{0}}{{\,}_{-1}}e}}\,\]
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