A) 6 and \[+\,3\]
B) 4 and\[-\,2\]
C) 3 and 0
D) 3 and\[+\,3\]
Correct Answer: A
Solution :
Key Idea: (i) Coordination of central atom is number of lone pair of electrons donated by ligands (ii) The sum of oxidation number of all elements in coordination compound is always zero. \[{{K}_{3}}[Cr{{({{C}_{2}}{{O}_{4}})}_{3}}]\] \[\because \]Oxalate is bidentate ligand so coordination number of \[\text{Cr}\,\text{=}\,\text{6}\] Let oxidation number of Cr in \[{{K}_{3}}[Cr{{({{C}_{2}}{{O}_{4}})}_{3}}]=x\] or \[(+\,1\,\times \,3)+x+(-2\times 3)=0\] or \[3+x-6=0\] \[\therefore \] \[x=+\,3\] \[\therefore \]Coordination number of Cr in given compound is 6 and oxidation number + 3
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