BCECE Engineering BCECE Engineering Solved Paper-2002

  • question_answer
    Which is the correct electronic configuration of Cr (chromium)?

    A) \[1{{s}^{2}}\text{ }2{{s}^{2}}\text{ }2{{p}^{6}}\text{ }3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }4{{s}^{1}}\text{ }3{{d}^{5}}\]

    B) \[1{{s}^{2}}\text{ }2{{s}^{2}}\text{ }2{{p}^{6}}\text{ }3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }4{{s}^{2}}\text{ }3{{d}^{4}}\]

    C) \[1{{s}^{2}}\text{ }2{{s}^{2}}\text{ }2{{p}^{6}}\text{ }3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }4{{s}^{2}}\text{ }3{{d}^{6}}\]

    D) \[1{{s}^{2}}\text{ }2{{s}^{2}}\text{ }2{{p}^{6}}\text{ }3{{s}^{2}}\text{ }3{{p}^{6}}\text{ }4{{s}^{1}}\text{ }3{{d}^{8}}\]

    Correct Answer: A

    Solution :

    Key Idea: Exactly half filled orbitals are more stable than nearly half filled orbitals At. no. of \[Cr=24\] \[\text{= 1}{{s}^{2}}\text{ }2{{s}^{2}},\text{ }2{{p}^{6}},\text{ }3{{s}^{2}},\text{ }3{{p}^{6}},\text{ }4{{s}^{1}},\text{ }3{{d}^{5}}\]


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