2. Solved Papers
  3. BCECE Engineering

BCECE Engineering BCECE Engineering Solved Paper-2002

  • question_answer
    On producing the waves of frequency 1000 Hz in a Kundts tube, the total distance between 6 L    successive nodes is 85 cm. Speed of sound in the gas filled in the tube is:

    A)  300 m/s                              

    B)  350 m/s

    C)  340 m/s              

    D)         330 m/s

    Correct Answer: C

    Solution :

    The relation between distance of successive nodes and wavelength of the wave is \[s=85=\frac{(n-1)\lambda }{2}=\frac{(6-1)\lambda }{2}=\frac{5\lambda }{2}\] \[\Rightarrow \]               \[\lambda =\frac{85\times 2}{5}=34\,cm=0.34\,m\] Speed of sound \[v=f\lambda ,\]where\[f\]is frequency and \[\lambda \]is wavelength. \[v=1000\times 0.34\,=340\,m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner