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BCECE Engineering BCECE Engineering Solved Paper-2001

  • question_answer
    The     roots     of     the     equation \[a({{x}^{2}}+1)-({{a}^{2}}+1)x=0\]are:

    A) \[a,\frac{1}{a}\]                                               

    B) \[a,2a\]

    C)         \[a,\frac{1}{2a}\]            

    D)         none of these

    Correct Answer: A

    Solution :

    We have \[a({{x}^{2}}+1)-({{a}^{2}}+1)x=0\] \[\Rightarrow \]\[a{{x}^{2}}-({{a}^{2}}+1)x+a=0\] \[\Rightarrow \]\[(a{{x}^{2}}-{{a}^{2}}x)-(x-a)=0\] \[\Rightarrow \]\[ax(x-a)-1(x-a)=0\] \[\Rightarrow \]\[(x-a)(ax-1)=0\] \[\Rightarrow \]               \[x=a,\frac{1}{a}\]


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