A) 5
B) 4
C) 6
D) 3
Correct Answer: D
Solution :
Key Idea: Draw all isomers and count them saturated pentane is \[{{\text{C}}_{\text{5}}}{{\text{H}}_{\text{12}}}\text{.}\] (i) \[\underset{\text{pentane}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}}}\,\] (ii) \[\underset{2-\,\text{methyl}\,\text{butane}}{\mathop{C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}-C{{H}_{3}}}}\,\] (iii) \[\underset{2,-2\text{dimethyl}\,\text{propane}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}}}\,\] \[\therefore \]Total number of 3 isomers are possible by\[{{C}_{5}}{{H}_{12}}\] (saturated pentane).
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