A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\]
B) \[C{{H}_{2}}BrC{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}-\underset{Br}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}\]
D) none of the above
Correct Answer: C
Solution :
Key Idea: Addition of unsymmetrical reagent across unsymmetrical double bond follows Markownikoff rule. According to this rule, the negative part of reagent adds to carbon atom having lesser number of hydrogen atoms. \[\underset{\text{propene}}{\mathop{C{{H}_{3}}-CH=C{{H}_{2}}}}\,+HBr\xrightarrow{{}}\] \[\underset{2-\text{bromopropane}}{\mathop{C{{H}_{3}}-\underset{Br}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}}}\,\] 1-bromopropane is obtained when same reaction takes place in presence of peroxide.
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