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BCECE Engineering BCECE Engineering Solved Paper-2001

  • question_answer
    The shape of \[\text{Xe}{{\text{O}}_{\text{4}}}\]molecule is tetrahedral due to:

    A)  \[sp\]                    

    B)        \[s{{p}^{2}}\]                        

    C) \[s{{p}^{3}}\]                        

    D)        none of these

    Correct Answer: C

    Solution :

    Key Idea: Hybridisation\[=\frac{1}{2}\] [No. of electron in valence shell of central atom + No. of monovalent atoms + Charge on anion - Charge on cation] For \[\text{Xe}{{\text{O}}_{\text{4}}}\] Hybridisation \[=\frac{1}{2}(8+0+0-0)\]                                 \[=4\] \[\therefore \]      \[s{{p}^{3}}\]hybridisation.


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