BCECE Engineering BCECE Engineering Solved Paper-2001

  • question_answer
    The critical angle for a medium is \[45{}^\circ \]. The refractive index will be:

    A) \[\frac{2}{\sqrt{3}}\]                                     

    B) \[\frac{\sqrt{3}}{2}\]                     

    C) \[\sqrt{2}\]                        

    D) \[\frac{1}{\sqrt{2}}\]

    Correct Answer: C

    Solution :

    The critical angle (C) is that angle of incidence for which the angle of refraction becomes \[{{90}^{o}}.\]It is given by, \[\sin C=\frac{1}{\mu }\] or                            \[\mu =\frac{1}{\sin C}\] or            \[\mu =\frac{1}{\sin {{45}^{o}}}\]             \[(\because \,C={{45}^{o}})\] or            \[\mu =\frac{1}{1/\sqrt{2}}=\sqrt{2}\] Note: Critical angle increases with increase in temperature of medium.


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