A) \[\frac{1}{4\pi {{\varepsilon }_{0}}}Ar_{0}^{3}\]
B) \[4\pi {{\varepsilon }_{0}}\,Ar_{0}^{3}\]
C) \[\frac{4\pi {{\varepsilon }_{0}}A}{r_{0}^{3}}\]
D) \[\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{A}{r_{0}^{3}}\]
Correct Answer: B
Solution :
: Intensity [E] at surface of sphere\[=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Q}{r_{0}^{2}}\] Since\[E=A{{r}_{0}}\] \[\therefore \] \[A{{r}_{0}}=\frac{Q}{4\pi {{\varepsilon }_{0}}r_{0}^{2}}\] or \[Q=4\pi {{\varepsilon }_{0}}Ar_{0}^{3}\]
You need to login to perform this action.
You will be redirected in
3 sec
