A) 16
B) 4
C) 2
D) ¼
Correct Answer: D
Solution :
: \[{{C}_{RMS}}=\sqrt{\frac{3RT}{M}}=\sqrt{\frac{3PV}{M}}\] \[\frac{{{C}_{O}}}{{{C}_{H}}}=\sqrt{\frac{{{M}_{H}}}{{{M}_{O}}}}=\sqrt{\frac{1}{16}}=\frac{1}{4}\] \[\therefore \]\[\frac{{{C}_{O}}}{{{C}_{H}}}=\frac{1}{4}\]
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