A) \[t\]
B) \[{{t}^{1/2}}\]
C) \[{{t}^{5/2}}\]
D) \[{{t}^{3/2}}\]
Correct Answer: D
Solution :
: Power P = (force F)\[\times \](velocity v) \[P=m\times \] acceleration\[\times v\] or \[P=ma\times (at)\Rightarrow {{a}^{2}}=\frac{p}{m\times t}\] Now\[S=\frac{1}{2}a{{t}^{2}}\] \[=\frac{1}{2}\times \sqrt{\frac{P}{mt}}.{{t}^{2}}=\frac{1}{2}\times \sqrt{\frac{P}{m}}.{{t}^{3/2}}\] S = (constant) \[\times {{t}^{3/2}}\] or Distance\[(S)\propto {{t}^{3/2}}\]
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