A) \[30\sqrt{2}\,m/s\]
B) \[10\sqrt{2}\,m/s\]
C) \[20\sqrt{2}\,m/s\]
D) \[20\,m/s\]
Correct Answer: C
Solution :
: Momentum is conserved \[\therefore \] (3mv) = Momentum of heavy particle \[\therefore \]\[mu=\]momentum of lighter particle \[{{(mu)}^{2}}+{{(mu)}^{2}}={{(3mv)}^{2}}\] or \[2{{m}^{2}}{{u}^{2}}=9{{m}^{2}}{{v}^{2}}\Rightarrow 2\times {{(60)}^{2}}=9{{r}^{2}}\] or \[{{v}^{2}}=\frac{2\times 60\times 60}{9}=2\times 400\] or \[v=20\sqrt{2}m/s\]
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