A) 3430 k. calories of energy
B) 343 k. calories of energy
C) 3030 k. calories of energy
D) 430 k. calories of energy.
Correct Answer: A
Solution :
: In the complete oxidation of one glucose molecule, 686 Kcal of energy is released. \[{{C}_{6}}{{H}_{12}}{{O}_{6}}+6{{O}_{2}}\to 6C{{O}_{2}}+{{H}_{2}}O+686\,Kcal\] Then, 5 molecules of glucose on oxidation will, release 3430 Kcal of energy.
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