A) \[7.48\times {{10}^{3}}J\]
B) \[6.48\times {{10}^{3}}J\]
C) \[5.48\times {{10}^{3}}J\]
D) \[4.48\times {{10}^{3}}J\]
Correct Answer: A
Solution :
: Translational kinetic energy \[=\frac{3nRT}{2}\] \[n=\]no. of moles \[R=\]gas constant \[T=\]Temperature \[KE=\frac{3\times 2\times 8.314\times 300}{2}=7.48\times {{10}^{3}}J\].
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