A) \[{{N}_{2}}O\]
B) \[N{{O}_{2}}\]
C) \[{{N}_{2}}{{O}_{4}}\]
D) \[N{{H}_{4}}N{{O}_{3}}\]
Correct Answer: A
Solution :
:\[4Zn+10HN{{O}_{3}}(dil.)\to 4Zn{{(N{{O}_{3}})}_{2}}+5{{H}_{2}}O\] \[+{{N}_{2}}O\]
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