A) \[2.25\times {{10}^{7}}J\]
B) \[2.25\times {{10}^{14}}J\]
C) \[6.75\times {{10}^{10}}J\]
D) \[4.5\times {{10}^{7}}J\]
Correct Answer: B
Solution :
: Energy liberated\[=m{{c}^{2}}\] \[=(1kg)\times \left( 3\times {{10}^{8}}\frac{m}{s} \right)\times \frac{0.25}{100}J\] \[=\frac{9\times {{10}^{16}}\times 0.25}{100}=2.25\times {{10}^{14}}J\]
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