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AMU Medical AMU Solved Paper-1998

  • question_answer
    Hole and electron mobilities of semiconductor are 0.05 and\[0.15\,{{m}^{2}}{{V}^{-1}}s\]. An electric field of strength\[4\text{ }Vc{{m}^{-1}}\]is applied to it. The ratio of drift velocities of electron and hole is

    A)  1                 

    B)  2

    C)  3                 

    D)  4

    Correct Answer: C

    Solution :

    : Drift velocity = electric field\[\times \]mobility or \[v=E\times \mu ,\] or \[\frac{{{v}_{e}}}{{{v}_{h}}}=\frac{E{{\mu }_{e}}}{E{{\mu }_{h}}}=\frac{{{\mu }_{e}}}{{{\mu }_{h}}}=\frac{0.15}{0.05}=\frac{3}{1}\]


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