A) \[15\,\mu F\]
B) \[30\,\mu F\]
C) \[20\,\mu F\]
D) \[10\,\mu F\]
Correct Answer: A
Solution :
: \[{{q}_{1}}=10\times 50=500\mu C\] \[{{C}_{1}}=10\mu F,{{C}_{2}}=?\] \[{{q}_{2}}=0\] As\[V=\frac{{{q}_{1}}+{{q}_{2}}}{{{C}_{1}}+{{C}_{2}}}\] \[\therefore \]\[{{C}_{1}}+{{C}_{2}}=\frac{{{q}_{1}}+{{q}_{2}}}{V}=\frac{500+0}{20}=25\,\mu F\] \[{{C}_{2}}=25-{{C}_{1}}=25-10=15\,\mu F\]
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