A) \[7.2\times {{10}^{-4}}N\]
B) \[18.0\times {{10}^{-4}}N\]
C) \[36.0\times {{10}^{-4}}N\]
D) none of the above
Correct Answer: C
Solution :
: Surface tension\[=\frac{Force}{2(length)}\] \[\therefore \] \[7.2\times {{10}^{-4}}\frac{N}{cm}=\frac{Force}{2(2.5)\text{ }cm}\] \[\therefore \] Force\[=7.2\times {{10}^{-4}}\times 2.5\times 2\,N\] \[=36.0\times {{10}^{-4}}N\]
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