AMU Medical AMU Solved Paper-1997

  • question_answer
    An electron starts from rest in an electric field and acquires a speed u in reaching a point A. The potential difference between the starting point and the point A is\[{{V}_{A}}\]

    A)  \[u\propto V_{A}^{2}\]

    B)  \[u\propto {{V}_{A}}\]

    C)  \[u\propto \sqrt{{{V}_{A}}}\]

    D)  \[u\propto V_{A}^{2/3}\]

    Correct Answer: C

    Solution :

    : Potential difference\[{{V}_{A}}=E\times distance\text{ }d\] Force on electron\[=Ee\] Acceleration of electron \[=\frac{Ee}{m}\] By using the third equation of motion, \[\therefore \] \[{{u}^{2}}=0+2\times \] (acceleration) \[\times S\] or \[{{u}^{2}}=2\frac{Ee}{m}\times d\]    or \[{{u}^{2}}=2Ed\frac{e}{m}\] or \[{{u}^{2}}=2{{V}_{A}}\frac{e}{m}\] or \[{{u}^{2}}\propto {{V}_{A}}\] or \[u\propto \sqrt{{{V}_{A}}}\]


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