A) halved
B) unchanged
C) doubled
D) quadrupled
Correct Answer: D
Solution :
\[\beta =\frac{D\lambda }{d}\] \[\therefore \]\[\frac{{{\beta }_{1}}}{{{\beta }_{2}}}=\left( \frac{{{D}_{1}}}{{{D}_{2}}} \right)\left( \frac{{{d}_{2}}}{{{d}_{1}}} \right)\]or\[\frac{{{\beta }_{1}}}{{{\beta }_{2}}}=\left( \frac{{{D}_{1}}}{{{D}_{1}}\times 2} \right)\left( \frac{{{d}_{1}}}{2\times {{d}_{1}}} \right)\] or \[\frac{{{\beta }_{1}}}{{{\beta }_{2}}}=\frac{1}{4}\] or \[{{\beta }_{2}}=4{{\beta }_{1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
