AMU Medical AMU Solved Paper-1996

  • question_answer
    The focal length of the objective of an astronomical telescope is 1.0 m if the magnifying power of the telescope is 20 the length of the telescope for relaxed eye in cm is

    A)  95               

    B)  105

    C)  120              

    D)  125

    Correct Answer: B

    Solution :

    : For a telescope for relaxed eye, Magnifying power\[M=\frac{{{f}_{o}}}{{{f}_{e}}}\] Tube length\[L={{f}_{o}}+{{f}_{e}}\] \[\therefore \]\[20=\frac{1.0}{{{f}_{e}}}\]or\[{{f}_{e}}=\frac{1}{20}m=\frac{100}{20}cm=5\,cm\] Tube length\[L={{f}_{o}}+{{f}_{e}}=(100+5)=105\text{ }cm\].


You need to login to perform this action.
You will be redirected in 3 sec spinner