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AMU Medical AMU Solved Paper-1996

  • question_answer
    If the electric dipole moment (of magnitude\[6.2\times {{10}^{-30}}m\]) of a water molecule is initially pointing in a direction opposite to that of an electric field of magnitude\[1.5\times {{10}^{-4}}N/C\] The work done by the field in rotating the molecule into alignment with the field.

    A)  \[-1.9\times {{10}^{25}}J\]    

    B)  zero

    C)  \[9.5\times {{10}^{-26}}J\]     

    D)  \[1.9\times {{10}^{-25}}J\]

    Correct Answer: D

    Solution :

    : Work done\[=pE(1-\cos \theta )\] \[=(6.2\times {{10}^{-30}})\times (1.5\times {{10}^{4}})(1-cos180{}^\circ )\] \[=2\times 6.2\times 1.5\times {{10}^{-26}};1.86\times {{10}^{-25}}J\] \[=1.9\times {{10}^{-25}}.\]


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