A) \[He_{2}^{+}\]
B) \[H_{2}^{+}\]
C) \[He_{2}^{+}\]and \[H_{2}^{+}\]
D) all the above
Correct Answer: D
Solution :
: The electronic configuration of\[H_{2}^{+}\] molecule ion is\[{{(\sigma 1s)}^{1}}\]. \[\therefore \]Bond order \[=\frac{1}{2}[{{N}_{b}}-{{N}_{a}}]=\frac{1}{2}[1-0]=\frac{1}{2}\] For \[He_{2}^{+},[\sigma 1{{s}^{2}},{{\sigma }^{*}}1{{s}^{1}}]\] Bond order \[=\frac{1}{2}(2-1)=\frac{1}{2}\].
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