A) \[\frac{Z{{e}^{2}}}{{{r}^{2}}}=\frac{m{{v}^{2}}}{{{r}^{2}}}\]
B) angular momentum is quantized
C) mass of proton is ignored
D) none of the above
Correct Answer: A
Solution :
: \[\frac{Z{{e}^{2}}}{{{r}^{2}}}=\frac{m{{v}^{2}}}{r}\]
You need to login to perform this action.
You will be redirected in
3 sec
