A) primary amine
B) secondary amine
C) tertiary amine
D) all the above
Correct Answer: A
Solution :
: Hoffmann bromamide reaction - \[R-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-N{{H}_{2}}+B{{r}_{2}}+4NaOH\xrightarrow[{}]{{}}RN{{H}_{2}}-2NaBr\] \[+N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O\]
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