A) directly proportional to its mass
B) directly proportional to its energy
C) inversely proportional to its momentum
D) directly proportional to its momentum
Correct Answer: C
Solution :
: de Broglie wavelength \[(\lambda )=\frac{h}{p}=\frac{h}{momentum}=\frac{h}{mv}\] \[\therefore \] \[\lambda \propto \frac{1}{momentum(mv)}.\]
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