A) U
B) Th
C) Ac
D) Pa
Correct Answer: C
Solution :
\[{{\,}_{89}}Ac=[Rn]\,6{{d}^{1}},7{{s}^{2}}\] Oxidation state = + 3 \[{{\,}_{90}}Th=[Rn]\,6{{d}^{2}},7{{s}^{2}}\] Oxidation states\[=+\,3,\,+4\] \[{{\,}_{91}}Pa=[Rn]\,6{{d}^{3}},7{{s}^{2}}\] Oxidation states \[=+\,3,+\,4,+\,5\] \[{{\,}_{92}}U=[Rn]\,6{{d}^{4}},7{{s}^{2}}\] Oxidation states \[=+3,\,+4,\,+5,\,+6\]
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