question_answer

Low spin complex of \[{{d}^{6}}\]cation in an octahedral field will have the following energy

Note: -  (\[{{\Delta }_{o}}=\] crystal field splitting energy in an octahedral field, P = electron pairing energy)

A) \[\frac{-12}{5}{{\Delta }_{o}}+p\]            

B) \[\frac{-12}{5}{{\Delta }_{o}}+3p\]          

C) \[\frac{-2}{5}{{\Delta }_{o}}+2p\]            

D) \[\frac{-2}{5}{{\Delta }_{o}}+p\]

Correct Answer: A

Solution :

\[\therefore \]   Total energy \[={{\Delta }_{o}}+P\]                                 \[=\left( +\frac{3}{5}\times 0-\frac{2}{5}\times 6 \right){{\Delta }_{o}}+P\]                                 \[=\frac{-12}{5}{{\Delta }_{o}}+P\]