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NEET AIPMT SOLVED PAPER MAINS 2012

  • question_answer
    The input resistance of a silicon transistor is 100 \[\Omega \]. Base current is changed by 40 \[\mu A\] which results in a change in collector current by 2 mA. This transistor is used as a common-emitter amplifier with a load resistance of 4 k\[\Omega \]. The voltage gain of the amplifier is

    A)  2000                     

    B)  3000     

    C)  4000                     

    D)  1000

    Correct Answer: A

    Solution :

    We know \[{{V}_{g}}=\beta \frac{{{R}_{L}}}{{{R}_{i}}}\] \[=\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}}\frac{{{B}_{L}}}{{{R}_{i}}}\]                       \[\left( \because \beta =\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}} \right)\] On putting given values \[{{V}_{g}}=\frac{2\times {{10}^{-3}}}{40\times {{10}^{-6}}}\times \frac{4\times {{10}^{3}}}{100}\] \[{{V}_{g}}=2000\]


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