NEET AIPMT SOLVED PAPER MAINS 2011

  • question_answer
    200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be \[2.57\times {{10}^{-3}}\] bar. The molar mass of protein will be                    \[(R=0.083\,\,L\,\,bar\,\,mo{{l}^{-1}})\]

    A)  \[51022\,\,g\,\,mo{{l}^{-1}}\]  

    B)  \[122044\,\,g\,\,mo{{l}^{-1}}\]

    C)  \[31011\,\,g\,\,mo{{l}^{-1}}\]                   

    D)  \[61038\,\,g\,\,mo{{l}^{-1}}\]

    Correct Answer: D

    Solution :

    \[\because \pi =CRT\] \[=\frac{w\times 1000}{M\times V(in\,mL)}\times RT\] \[\left[ \because \text{C}\,\text{=}\frac{\text{n}\,\text{ }\!\!\times\!\!\text{ 1000}}{\text{V(in}\,\text{mL)}}\text{and}\,\text{n}\,\text{=}\frac{\text{w}}{\text{M}} \right]\] \[\,\text{=}\frac{1.26\times 1000\times 0.083\times 300}{2.57\times {{10}^{-3}}\times 200}\] \[=61038\,g\,mo{{l}^{-1}}\]


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