NEET AIPMT SOLVED PAPER MAINS 2011

  • question_answer
    Which of the following complex compounds will exhibit highest paramagnetic behaviour? \[(At.\,no.:Ti=22,Cr=24,Co=27,Zn=30)\]

    A) \[{{[Ti{{(N{{H}_{3}})}_{6}}]}^{3+}}\]        

    B) \[{{[Cr{{(N{{H}_{3}})}_{6}}]}^{3+}}\]

    C) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]      

    D) \[{{[Zn{{(N{{H}_{3}})}_{6}}]}^{2+}}\]

    Correct Answer: B

    Solution :

    [a] Electronic configuration of \[\text{T}{{\text{i}}^{\text{3+}}}\] in \[{{[Ti{{(N{{H}_{3}})}_{6}}]}^{3+}}\] [b] Electronic configuration of \[\text{C}{{\text{r}}^{\text{3+}}}\]in\[{{\text{ }\!\![\!\!\text{ Cr(N}{{\text{H}}_{\text{3}}}{{\text{)}}_{\text{6}}}\text{ }\!\!]\!\!\text{ }}^{\text{3+}}}\] [c] Electronic configuration of \[\text{C}{{\text{O}}^{\text{3+}}}\]in\[{{\text{ }\!\![\!\!\text{ Co(N}{{\text{H}}_{\text{3}}}{{\text{)}}_{\text{6}}}\text{ }\!\!]\!\!\text{ }}^{\text{3+}}}\text{:}\] In the presence of strong field ligand \[N{{H}_{3}},\]pairing of electrons takes place and thus, octahedral    complex,\[{{\text{ }\!\![\!\!\text{ Co(N}{{\text{H}}_{\text{3}}}{{\text{)}}_{\text{6}}}\text{ }\!\!]\!\!\text{ }}^{\text{3+}}}\]   is diamagnetic. \[{{\text{ }\!\![\!\!\text{ Co(N}{{\text{H}}_{\text{3}}}{{\text{)}}_{\text{6}}}\text{ }\!\!]\!\!\text{ }}^{\text{3+}}}\] \[\left[ \begin{align}   & \text{inner}\,\text{orbital}\,\text{or} \\  & \text{low}\,\text{spin}\,\text{complex} \\ \end{align} \right]\text{(6N}{{\text{H}}_{\text{3}}}\,\text{molecules)}\] [d] Electronic configuration of\[Z{{n}^{2+}}\] in \[{{[Zn{{(N{{H}_{3}})}_{6}}]}^{2+}}:\] \[\therefore \]\[{{[Zn{{(N{{H}_{3}})}_{6}}]}^{2+}}\]is an outer orbital complex and is diamagnetic.


You need to login to perform this action.
You will be redirected in 3 sec spinner