NEET AIPMT SOLVED PAPER MAINS 2011

  • question_answer
    Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the centre of the ring is              

    A) \[\frac{{{\mu }_{0}}qf}{2R}\]     

    B) \[\frac{{{\mu }_{0}}q}{2f\,R}\]  

    C) \[\frac{{{\mu }_{0}}q}{2\pi f\,R}\]           

    D) \[\frac{{{\mu }_{0}}qf}{2\pi R}\]

    Correct Answer: A

    Solution :

    We know \[B=\frac{{{\mu }_{0}}i}{2R}\] \[q=it\Rightarrow i=\frac{q}{t}=qf\]        \[\left[ \because \,\,f=\frac{1}{t} \right]\] \[B=\frac{{{\mu }_{0}}qf}{2R}\]


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