A) p-type with electron concentration \[{{n}_{e}}=5\times {{10}^{22}}\,{{m}^{-3}}\]
B) p-type with electron concentration \[{{n}_{e}}=2.5\times {{10}^{10}}\,{{m}^{-3}}\]
C) n-type with electron concentration \[{{n}_{e}}=2.5\times {{10}^{23}}\,{{m}^{-3}}\]
D) p-type having electron concentration \[{{n}_{e}}=5\times {{10}^{9}}\,{{m}^{-3}}\]
Correct Answer: D
Solution :
\[n_{i}^{2}={{n}_{e}}{{n}_{h}}\] \[{{n}_{e}}=\frac{{{({{n}_{i}})}^{2}}}{{{n}_{h}}}\] \[{{n}_{e}}=\frac{{{(1.5\times {{10}^{16}})}^{2}}}{(4.5\times {{10}^{22}})}\] \[{{n}_{e}}=5\times {{10}^{9}}{{m}^{-3}}\] So,\[{{n}_{h}}>>{{n}_{e}}\] semiconductor is p -type.
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