A) + 10.3 kJ
B) - 43.3 Kj
C) - 10.3 kJ
D) + 6.2 kJ
Correct Answer: D
Solution :
Given, (I)\[F{{e}_{2}}O(s)+3CO(g)\xrightarrow[{}]{{}}2Fe(s)+3C{{O}_{2}}(g);\]\[\Delta H=-26.8\,\text{kJ}\] (II)\[FeO(s)+CO(g)\xrightarrow[{}]{{}}Fe(s)+C{{O}_{2}}(g);\]\[\Delta H=-16.5\,\text{kJ}\] On multiplying Eq (II) with 2, we get (III) \[2FeO(s)+2CO(g)\xrightarrow[{}]{{}}2Fe(s)+2C{{O}_{2}}(g);\]\[\Delta H=-33\,\text{kJ}\] On subtracting Eq (III) from I, we get \[F{{e}_{2}}{{O}_{3}}(s)+CO(g)\xrightarrow[{}]{{}}2FeO(s)+C{{O}_{2}}(g);\]\[\Delta H=-26.8-(-33)\] \[=+6.2\,\text{kJ}\]
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