| List I (Equations) | List II (Type of process) |
| A. \[{{K}_{p}}>Q\] | 1. Non-spontaneous |
| B. \[\Delta {{G}^{o}}<RT\,\ln Q\] | 2. Equilibrium |
| C. \[{{K}_{p}}=Q\] | 3. Spontaneous and endothermic |
| D. \[T>\frac{\Delta H}{\Delta S}\] | 4. Spontaneous |
A) A-1 B-2 C-3 D-4
B) A-3 B-4 C-2 D-1
C) A-4 B-1 C-2 D-3
D) A-2 B-1 C-4 D-3
Correct Answer: C
Solution :
[A] When\[{{K}_{p}}>Q,\]the reaction goes in forward direction, ie, the reaction is spontaneous. [B] Given, \[\Delta {{G}^{o}}<RT\ln Q,\]thus, \[\Delta {{G}^{o}}=+\,ve\]and hence, the reaction is non- spontaneous. [C] At equilibrium, \[{{K}_{p}}=Q\]( [D] \[T>\frac{\Delta H}{\Delta S}\] or \[T\Delta S>\Delta H\] This condition is true for spontaneous endothermic reactions \[(\text{as}\,\Delta G\ge \Delta H-T\Delta H).\]
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