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JEE Main & Advanced AIEEE Solved Paper-2013

  • question_answer
    If\[P=\left[ \begin{matrix}    1 & \alpha  & 3  \\    1 & 3 & 3  \\    2 & 4 & 4  \\ \end{matrix} \right]\]is the ad joint of\[3\times 3\]matrix A and \[|A|=4,\] then \[\alpha \] is equal to:     AIEEE Solevd Paper-2013

    A) 4             

    B)                        11                          

    C)        5                             

    D)        0

    Correct Answer: B

    Solution :

    \[\because \]\[1\left| \begin{matrix}    1 & \alpha  & 3  \\    1 & 3 & 3  \\    2 & 4 & 4  \\ \end{matrix} \right|1=|A{{|}^{2}}={{4}^{2}}\] \[2\alpha -6=16\]                             \[\therefore \] \[\alpha =11.\]


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