A) lies between 1 and 2
B) lies between 2 and 3
C) lies between −1 and 0
D) does not exist
Correct Answer: D
Solution :
\[f(x)=2{{x}^{3}}+3x+k\] \[f'(x)=6{{x}^{2}}+3\] \[f'(x)=0\] \[\Rightarrow \]\[{{x}^{2}}=-\frac{1}{2}\] Not Possible. As condition for two distinct real root is\[f(\alpha )\] \[f(\beta )=0\] (where\[\alpha ,\beta \]are roots of\[f'(x)=0\])
You need to login to perform this action.
You will be redirected in
3 sec
