JEE Main & Advanced AIEEE Solved Paper-2013

  • question_answer
    If the vectors \[\overrightarrow{AB}=3\hat{i}+4\hat{k}\]and \[\overrightarrow{AC}=5\hat{i}-2\hat{j}+4\hat{k}\]are the sides of a triangle ABC, then the length of the median through A is:     AIEEE Solevd Paper-2013

    A) \[\sqrt{18}\]                      

    B) \[\sqrt{72}\]      

    C)        \[\sqrt{33}\]      

    D)        \[\sqrt{45}\]

    Correct Answer: C

    Solution :

    Median through ?A? is \[\frac{(3\hat{i}+3\hat{k})+(5\hat{i}-2\hat{j}+4\hat{k})}{2}\] \[=4\hat{i}-\hat{j}+4\hat{k}\] So, Length \[=\sqrt{{{4}^{2}}+{{1}^{2}}+{{4}^{2}}}=\sqrt{33}\]


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