JEE Main & Advanced AIEEE Solved Paper-2013

  • question_answer
    Distance between two parallel planes\[2x+y\] \[+2z=8\] and\[4x+2y+4z+5=0\text{ }is:\]     AIEEE Solevd Paper-2013

    A) \[\frac{3}{2}\]                   

    B)        \[\frac{5}{2}\]                   

    C)        \[\frac{7}{2}\]                   

    D)        \[\frac{9}{2}\]

    Correct Answer: C

    Solution :

    Planes are \[2x+y+2z-8=0\text{ }\And \text{ }2x+y+2z+\frac{5}{2}=0\] Distance is \[=\frac{\frac{5}{2}-(-8)}{\sqrt{{{2}^{2}}+{{1}^{2}}+{{2}^{2}}}}=\frac{\frac{21}{2}}{3}=\frac{7}{2}\]


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