A) \[-2.55\text{ }eV\]
B) \[-5.1\text{ }eV\]
C) \[-10.2\text{ }eV\]
D) \[+2.55\text{ }eV\]
Correct Answer: B
Solution :
E.A. = Ionisation potential \[\therefore \]EA of\[N{{a}^{+}}=-5.1\text{ }eV\]
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