A) \[y=x-5{{x}^{2}}\]
B) \[y=2x-5{{x}^{2}}\]
C) \[4y=2x-5{{x}^{2}}\]
D) \[4y=2x-25{{x}^{2}}\]
Correct Answer: B
Solution :
\[u=\sqrt{{{2}^{2}}+{{1}^{2}}}=\sqrt{5}\] \[\theta =ta{{n}^{-1}}2\] Equation: \[y=x\text{ }tan\text{ }\theta -\frac{g{{x}^{2}}}{2{{u}^{2}}{{\cos }^{2}}\theta }\] \[y=2x-\frac{10{{x}^{2}}}{2\times 5\times \frac{1}{5}}\] \[y=2x-5{{x}^{2}}\]
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