JEE Main & Advanced AIEEE Solved Paper-2013

  • question_answer
    The above \[p-v\] diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle is:     AIEEE Solevd Paper-2013

    A) \[{{p}_{0}}{{v}_{0}}\]     

    B)        \[\left( \frac{13}{2} \right){{p}_{0}}{{v}_{0}}\]    

    C)        \[\left( \frac{11}{2} \right){{p}_{0}}{{v}_{0}}\]    

    D)        \[4{{p}_{0}}{{v}_{0}}\]

    Correct Answer: B

    Solution :

    Heat extracted from the source \[=\frac{{{C}_{V}}}{R}({{P}_{2}}{{V}_{2}}-{{P}_{1}}{{V}_{1}})+\frac{{{C}_{P}}}{R}({{P}_{3}}{{V}_{3}}-{{P}_{2}}{{V}_{2}})\] \[=\frac{3{{P}_{0}}{{V}_{0}}}{2}+5{{P}_{0}}{{V}_{0}}=\frac{13}{2}{{P}_{0}}{{V}_{0}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner