JEE Main & Advanced AIEEE Solved Paper-2012

  • question_answer
    If \[g(x)=\int\limits_{0}^{x}{\cos 4t\,\,dt}\], then \[g(x+\pi )\] equals   AIEEE  Solved  Paper-2012

    A) \[\frac{g(x)}{g(\pi )}\]                                      

    B) \[g(x)+g(\pi )\]

    C) \[g(x)-g(\pi )\]        

    D) \[g(x).\,g(\pi )\]

    Correct Answer: B

    Solution :

                 \[g(x+\pi )=\int\limits_{0}^{x+\pi }{\cos 4\,dt=g(x)+\int\limits_{0}^{\pi }{\cos 4t\,dt}}\]                    \[=g(x)+g(\pi )\] Here \[g(\pi )=\int\limits_{0}^{\pi }{\cos 4t\,dt=0}\] so answers are (b) or (c)


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