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JEE Main & Advanced AIEEE Solved Paper-2012

  • question_answer
    The standard reduction potentials for \[Z{{n}^{2}}/Zn,N{{i}^{2+}}/Ni\] and \[F{{e}^{2+}}/Fe\] are \[-0.76,-0.23\]and \[-0.44\] V respectively. The reaction \[X+{{Y}^{2}}+\to {{X}^{2+}}Y\] will be spontaneous when :   AIEEE  Solved  Paper-2012

    A) \[X=Ni,\,Y=Fe\]   

    B) \[X=Ni,\,Y=Zn\]

    C) \[X=Fe,\,Y=Zn\]  

    D) \[X=Zn,\,Y=Ni\]

    Correct Answer: D

    Solution :

                 \[X+{{Y}^{2+}}\xrightarrow{{}}{{X}^{2+}}+Y\]For reaction to be spontaneous \[{{E}^{o}}\] must be positive. \[{{E}^{o}}_{Zn/Z{{n}^{+2}}}+{{E}^{o}}_{N{{i}^{2+}}/Ni}=0.76+(-0.23)=+0.53\](positive)


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