A) efficiency of carnot engine cannot be made larger than 50%
B) 1200 K
C) 750 K
D) 600 K
Correct Answer: C
Solution :
For 1st case efficiency \[\eta =\left( 1-\frac{{{T}_{1}}}{{{T}_{2}}} \right)\times 100\] \[\left( 1-\frac{{{T}_{1}}}{500} \right)\times 100=40\] \[{{T}_{1}}=300\,\,K\] for 2nd case \[\eta =\left( 1-\frac{300}{{{T}_{2}}} \right)\times 100=60\] \[{{T}_{2}}=750\,K\]
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