JEE Main & Advanced AIEEE Solved Paper-2012

  • question_answer
    Assume that a neutron breaks into a proton and an electron. The energy released during this process is : (mass of neutron \[=1.6725\times {{10}^{-27}}kg\], Mass of proton \[=1.6725\times {{10}^{-27}}kg\], mass of electron \[=9\times {{10}^{-31}}kg\])   AIEEE  Solved  Paper-2012

    A) 0.73 MeV                               

    B) 7.10 MeV

    C) 6.30 MeV                               

    D) 5.4 MeV

    Correct Answer: A

    Solution :

                 \[_{0}{{n}^{1}}{{\to }_{1}}{{H}^{1}}{{+}_{-1}}{{e}^{0}}+\overline{v}+Q\]               \[\Delta m={{m}_{n}}-{{m}_{\alpha }}-{{m}_{e}}\]              \[=(1.6725\times {{10}^{-27}}-1.6725\times {{10}^{-27}}-9\times {{10}^{-31}})kg\]              \[=-9\times {{10}^{-31}}kg\]s      Energy \[=9\times {{10}^{-31}}\times {{(3\times {{10}^{8}})}^{2}}\] \[=0.511\] MeV Which is nearly equal to 0.73 Mev but as energy will be required. since mass is increasing so answer \[=-0.511\] Mev either (a) or bonus.


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