A) \[\frac{5}{2}\] square units
B) \[\frac{1}{2}\] square units
C) 1 square units
D) \[\frac{3}{2}\] square units
Correct Answer: D
Solution :
Required area \[=\,\,\frac{1}{2}\times 1\times 1+\int\limits_{1}^{e}{\frac{1}{x}dx}\] \[=\frac{1}{2}+[Inx]_{1}^{e}\] \[=\frac{1}{2}+1-0=\frac{3}{2}\] sq. unitsYou need to login to perform this action.
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