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JEE Main & Advanced AIEEE Solved Paper-2011

  • question_answer
    A vessel at 1000 K contains \[C{{O}_{2}}\] with a pressure of \[0.5\] atm. Some of the \[C{{O}_{2}}\] is converted into CO on the addition of graphite. If the total pressure at equilibrium is \[0.8\] atm, the value of K is.   AIEEE  Solved  Paper-2011

    A) \[0.18\] atm                          

    B) \[1.8\] atm

    C) 3 atm                                       

    D) \[0.3\] atm

    Correct Answer: B

    Solution :

                                    \[C{{O}_{2}}(g)+C(s)\overset{{}}{leftrightarrows}2CO\] at 1000 K \[P=0.5\] atm                     0                     \[0.5-p\]                             2p According to given condition          \[0.5+p=0.8\]                                                                    \[p=0.3\] So, \[{{K}_{P}}=\frac{{{(0.6)}^{2}}}{(0.2)}=\frac{0.36}{0.2}=1.8\] atm


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